0.01x^2-0.44x+1=0

Solution for 0.01x^2-0.44x+1=0 equation:

0.01x^2-0.44x+1=0

a = 0.01; b = -0.44; c = +1;
Δ = b2-4ac
Δ = -0.442-4·0.01·1
Δ = 0.1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.44)-\sqrt{0.1536}}{2*0.01}=\frac{0.44-\sqrt{0.1536}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.44)+\sqrt{0.1536}}{2*0.01}=\frac{0.44+\sqrt{0.1536}}{0.02}
$